Sudoku champion:
[tab]4 3 6 5 1 2
2 1 3 6 4 5
5 2 4 3 6 1
3 4 2 1 5 6
1 6 5 2 3 4
6 5 1 4 2 3[/tab]
How many triangles weighs a circle?[tab]s = c+t
c = t+p
2s = 3p
s = 3/2 p
p = 2/3 s
c = t + 2/3 s = 2/3 c + 2/3 t
1/3 c = 2/3 t
c = 2t
1 circle = two triangles[/tab]
And speaking of Sudoku:
In case you do not know the rules:
Numbers 1 through 9 on each row, column, and square region of 9.
That is false, James, because each brick must contain an odd and an even number!
Oops … forgot that rule 
That is false too, James.
I had to interpret your English intention. Could you reword it, seeing how I am solving for it? Your “with” and “and” are ambiguous.
And the correction for the first one:[tab]2 3 6 5 1 4
4 2 3 6 5 1
6 1 4 3 2 5
3 5 2 1 4 6
1 4 5 2 6 3
5 6 1 4 3 2[/tab]
Englsih intention? Reword it?
Your equations show me that you have understood my text correctly.
Howsoever. Maybe the following three pictures will help:
Ahhh … I see that I left out a “t” 
[tab]s = c+t [that is the 1st pic]
c = t+p [that is the 2nd pic]
2s = 3p [that is the 3rd pic]
from 3rd:
s = 3/2 p
p = 2/3 s
from 2nd:
c = t + 2/3 s
from 1st:
c = t + 2/3 c + 2/3 t
c - 2/3 c = t + 2/3 t
1/3 c = t + 2/3 t
c = 5t[/tab]
And in case you missed it from above:
Well done, James. =D>
Concerning the Uncle and Niece:
[tab]When I read “special birthday” I just dropped it. I dislike trying to figure out what someone might think of as a “special birthday”
But later, just making guesses, I came up with a “special birthday” being 50, in which case the people could be:
7
7
50
While the Uncle is 55 and the niece 32.
I have no idea of that is the kind of thing that you were expecting.[/tab]
9 6 7 | 4 3 5 | 2 8 1
5 1 3 | 2 8 6 | 7 4 9
8 4 2 | 7 1 9 | 6 3 5[/tab]
Well done. =D>
[tab]For the age of the three persons (x, y, z):
x • y • z = 2450 = 2 • 5 • 5 • 7 • 7.
The “special birthday” is the 50th (= 2 • 5 • 5). The three persons are 50, 7, and 7 years old; the uncle is 55 years old (= 50 + 5); the niece is 32 years old (= (50 + 7 + 7) / 2).[/tab]
Your watch has stopped. So it does not work anymore. The little hand of the watch indicates approximately ten o’clock, and the big hand of the watch indicates approximately two o’clock. Both hands of the watch form an identical angle. When did your watch stop precisely?
I hate always being the only kid in the class with his hand up.
Really?
Well I got deadlines and shit. Haven’t even been able to read this thread lately.
Who is the question directed to, the wearer of the watch or somebody else who sees the watch? If the latter, it depends on how fast he is moving when he observes the watch.
Right James?
JAMES! Wake up!
Um …Huh?
yeah, right.
Whuh?
Oh …
Actually the relativistic concerns involve the fact that the minute hand is moving faster than the hour hand and the observational angle, as well as the relative speed of the observer to the appearance of simultaneity of the event.
But then again, we can assume that he asked of the actuality, not the relative appearance.
There is no problem with the text, and the task is a pure mathematical one.
So again:
Carleas!
Please come to the blackboard!
This has to be a trick question. Arminius is too smart to ask a question that is so obviously answered with “10:00 is when the clock stopped.” So, what’s the trick dude? Nobody’s playing so just give us the answer mmkay?
And what is an identical angle, anyway?
I think it is a little bit too early to give you the answer.
Both angles have the same degree. The angular degree is the same.