Galaxies as atoms.

Anyway, thank you very much, James.

May wishes come true or not. I don’t know, whether the fractal theory is right, but I would like it to be. :slight_smile:

You know, there are much motions in the universe, and I believe that this motions are cyclic or spiral - both in nature and in culture (incl. civilisation).

Realize that the physical universe contains absolutely no geometric forms at all. Geometric forms are entirely a cartoon image within the mind and can never exist in the physical world expect as an average over an infinite amount of time.

There are cyclic motions, such as a electrons and planets orbiting. But even those are not as simple as thought and taught. An electron does not follow any specific path. It is guided by the precise field surrounding it (of which is it actually made). It never really takes the exact same course in all of its uncountable orbits.

I know that, James, but it is just my favourite model - not more. Geometric forms are also used as models or patterns. Mathematics can make happy, but not as much as music because music is the best. Now mathematics and music are reminding me again of Pythagoras and some posts:

viewtopic.php?f=4&t=185313&p=2460946#p2460946
viewtopic.php?f=4&t=185313&p=2460946#p2460974
viewtopic.php?f=4&t=185313&p=2460946#p2461028
viewtopic.php?f=4&t=185313&p=2460946#p2461067

Arminius said: Geometric forms are also used as models or patterns. Mathematics can make happy, but noct as much as music because music is the best.

Arminius, let me explain- 85% of spiral galaxies show a warp on each side ( and they
can’t see the rest well-enough to determine ).
Now- if my theory is to be correct, this means that galactic discs are
PRECESSING as well as rotating- which would cause the disc to
sweep out a sphere over 250 million years or whatever.
And they have recently measured how long electrons take to come back
to where they started: about 150 attoseconds. So that would be how
long it would take an atomic disc to turn once.

So, if you have a disc of electrons precessing once every 150 attoseconds,
it will look very much like a sphere.

Now, we know the diameter of the Milky Way, and we know the
diameter of a Carbon atom, so let’s compare:

Does 250 million years divided by 150 attoseconds
EQUAL
10^22 meters (dia. of Milky Way)
divided by 10^-9 meters (dia. of Carbon atom) ???

And, if you appreciate music, please listen to
this new song by a young artist
youtu.be/lTciiXHNkTE

Great song.

physicsworld.com/cws/article/new … d-accuracy

Here’s the reference for the electron’s cycle
as being 150 attoseconds.
Now, 250 million year, approximately, is the time
it takes for the Milky Way disc to rotate once.

So, since their diameters are 10^22 (approx) meters and
10^-9 (approx) meters, then, obviously,
the approximate ratio is 10^31.

Okay, 225 milion years = 7.9 X 10^15 seconds
and 150 attoseconds = 1.5 X 10^-16 seconds

So, by division, we get 5.3 X 10^31

Voila

Well done, but my question refered to your pictures, namely: what do the points symbolise? Electrons? Galactic arms?

And by the way this pictures too:

Help me, Helper!

Thank you.

The points represent where an
electron or a galactic arm would
go if it were part of a disc that
is both spinning and precessing.
In both the above pictures, the
disc spins once every time it
precesses once- in the Benzene
animation, the disc spins once
every time it precesses twice.

So the answer is: YES, the points represent electrons and galactic arms.

Thank you, Helper.

Great pics though, aren’t they.

Thanks, James!

I had an idea this model with one
rotation every two precessions could solve the Benzene ring thing,
so I started with this:

I had to make a number of educated guesses:

all the rings are always parallel, i.e. they all
precess the same way at the same rate

neighbouring discs always face the opposite direction,
rotating in opposite directions,
which means when their edges come together they will be
going the same way

I found that when placed in a hexagon, the edges come together
in 30 degree increments, i.e. like a clock face with numbers
1 through 12

I designated the clock face, when facing
the viewer, to be going clockwise.
So, I started all the discs with the 12 at the top,
and every second disc to be facing (and rotating)
the opposite direction. When the edges come together,
it is the same number on each disc, and I turn those numbers
from red to blue.

Notice- adjacent discs contact each other FOUR times
in one cycle- C3 and C4 connect at numbers 1, 4, 7 and 10

over and over and over…

Okay, continuing on explaining how I built Benzene:

Each disc in the ring has three neighbours, the other
two Carbon atoms and their own Hydrogen atom.

Each neighbour is contacted in 4 places.
Look at C3- it contacts C4 at the 1, 4, 7 and 9, as I
said above, while it contacts C2 at the 3, 6, 9 and 12
Then, it is also contacting the H3 disc at 2, 5, 8 and 11

However, the H3 doesn’t use two of those contacts, since
it has at most 2 electrons. So, it was decided to use
5 and 11 and leave 2 and 8 unused.

And this means, that on C3, the 2 and 8 slot
are not needed, so that is where I placed its
pair of bound electrons, and coloured them black
because they are not involved in the sharing.

Similarly, each of the other discs has two black
spheres representing its pair of bound electrons-
which I think is equivalent to the galaxy’s bar.
The Milky Way has a bar and 4 arms, recent data show.

Cool, hey? I’ll continue later.

Okak, once position 2 and 8 on C3 were designated for
the two bound (non-sharing) electrons, then all
the other trading and non-trading positions on
the other Carbons and Hydrogens are known on
examination and are shown on the above animation.
The non-trading positions are the black spheres representing
the one full, non-sharing orbital, and there will be one more
non-trading position on each Carbon, not known until later-
til the end, really.

Now we have the template for Benzene.
We know which positions are trading, we just don’t
know which will be empty or full when, and if
we just start randomly trading (I tried), and let
it run, the distribution becomes very unequal.
I mean, it still runs, but sometimes Carbons
have 2 or 3 extra, or are short 2 or 3 as it
cycles. So, the goal is complete symmetry, where
no position ever has fewer than 5 or more than
7 total.

Hard to do, let me tell you. It’s like a Sudoku.
That’s why I put a white sphere at every position,
at first, which will be easy to change color to
represent the presence of the electron- and eventually
remove completely when the electron isn’t there.

Okay, let’s look at the first step- the Carbon-Carbon
bond on each side of the ring- check it out:
(I love the format of this forum)

Oh, I forgot, I also decided to enlarge them, which was a monumental
pain, as it turned out.

Notice, each orbital has a yellow and a red, and the yellow goes into
the empty atomic orbital first, and the red goes on last.

Cool, hey?

I’ll continue later

Okay, now, looking at the above animation,
we have the 3 and 9 being exchanged
between C2 and C3 on one side of the ring and
also between C5 and C6 on the other.
That accounts for four of the 30 electrons
being exchanged.

Notice that there are two more
pairs of discs that meet at the 3 and the 9-
C1 and it’s Hydrogen, and C4 and its Hydrogen.
I chose these as the next 4 electrons to place.
There were two ways this could have been done-
and I agonized about it, and went with symmetry:

Okay, remember before, when the yellow went into the empty
pathway first? Well, I was trying to do that again, but ended up with
the red going in first. It doesn’t really matter- I only made
opposite members of the pathway be different colours in
order to keep from being confused when I was building each
frame in AutoCad.
However, what I did above, you’ll notice, is to not
show the pathway when there is nothing in it, show
each pathway in red when there is a single electron in it, and show
it in yellow when there are two electrons in it. I still
don’t know if that improves it.

The next step, after I tried many, many approaches, turned
out to be a simple copy and paste to what I already had from
24 and 48 frames ahead after a 120 and 240 degree rotation.
And it worked like a charm- I now had found the perfect
way to share 24 of the requisite 30, as you see below

A question :smiley:

Is this your math or is it already in existence? and what applications could it have for industry?

I guess it’s ‘my math’.
When I saw them getting results for the period
of the atom, I realized that it could
be compared to the period of a galaxy
because I regard them both as turning discs.
We already have pretty good figures for the
diameters of atoms and galaxies, so I thought
I’d do the comparison.

What applications can the whole model have for
industry? Right off the bat we’ll be able to
manipulate atomic orientation much, much
better. Crystallized plastics will be easy- harder
than diamond, but flexible and super-light.
Crystallized metals will make possible the thinnest
of thin metal foils that are virtually impermeable
to any cut or burn. We’ll be able to manipulate gravity.

Anyway, with reference to the picture above,
each disc’s edge meets it neighbour’s edge four
times per cycle (becuase it precesses twice per rotation).
Zoom in on the pic by holding control and hitting the +
five or six times- see the front two Carbons sharing
the 1 and the 7, but the 4 and the 10 are
still available?
Those available slots were where we
must now place our last 6 sharing electrons.
Sounds easy, but it’s not. It’s like a
Sudoku- I had to write it all out and display
it like a chart, and then overlay the different
posasible patterns- There was only one
possible solution at this point.

Each Carbon borrows from one neighbour
and gives to the other neighbour. I have coloured the
electrons and the
pathways green, and only show the pathway when
there is an electron present.

30 is the absolute maximum number of electrons
that can be shared with this structure, is what
I found. Now, if you zoom in on the C3-C4 connection,
you see three of the four meetings being used-
the 1, the 4 and the 7 are sharing while
the 10 does not. This is a bond and a half.

Actually, if you look at any of the C-C
trades, what you see is a yellow trade one way,
a green trade the opposite way, and then a red trade
the first way, followed by a blank, then a yellow
trade coming oppositely, a green coming oppositely,
and a red returning, followed by a blank.

I think I got them all in
the right place! :slight_smile:

The galaxies out there are ATOMS in some
infinitesmal corner of some expanding gas cloud
on some
planet orbitting some sun, itself orbitting
along with 100 million other suns
the center of the next sized galaxy up.

Which is, itself, an atom

And our atoms are also galaxies, and their electrons
are each 100 million stars or however many there are
in the average galactic arm

And those stars radiate emr of all
types that is around 31 orders of magnitude
smaller than our emr. And that emr affects us
by causing gravity and inertia, and is
involved in the ‘subtle vibrations’ that
shamans and whatnot have always spoken of