Nah. “Some” people are claiming that “1 group of three pies” divided into “3” equal parts is “1 pie”. Noone is saying “1 divided by 3 is 1”. That’s your own invention. The point is that when you take 1 group of three pies and divided it into 3 equal parts ( an operation equivalent to the operation of “1 divided by 3” ), you get a result, that result being “1 pie”. That tells us that “1 divided by 3” does have a result.
Your entire argument, so far, has been that, because we can’t find the base-10 representation of the result of the operation of dividing 1 by 3, it follows that such a result does not exist. That’s based on an unstated premise that, if a number does not have a base-10 representation, that that number does not exist. That is false. It is false because base-10 system of notation does not cover all numbers.
You’ve been already told that the result of “1 divided by 3” has a representation in base-3 system, namely, (0.1_3). But your response to that was that (0.1_3) is a result of (1_3) divided by (10_3) rather than 1 divided by 3. Obviously, you don’t understand the difference between a representation of a number and a number itself. You don’t understand that “(1_3) divided by (10_3)” and “1 divided by 3” are two different expressions of one and the same number. And you don’t understand that (0.1_3) is the result of BOTH operations ( given that they are one and the same operation. )
If, on the other hand, all you want to say is that 1/3 has no base-10 representation, then why don’t you say so? Noone disputes that.
I divided “1 group of three pies” into “3” equal parts.
I never actually came to that conclusion. “1 divided by 3” isn’t “1 pie”. Rather, “1 group of three pies” divided by “3” is “1 pie”. And that is relevant because “1 group of three pies divided by 3” is an instance of “1 divided by 3”.
I didn’t use math. I simply took 1 group of three pies and split it into 3 equal parts. I did it manually.
“1 group of three pies” is an example of “1 group”.
I’m sure that, had I used “1 group of one hundred pies” to support your claim, you’d have nothing against it. I’m sure you wouldn’t have said a single word against it. But because I am using something that disproves your silly claim, you’re desperately trying to render it as invalid. But you’re not doing a good job at it.
“1 group of three pies” is an instance of “1 group” and an instance of “1”.