Right, so the 2% has NOTHING to do with the chance of pulling a red ball.
Agree?
No
Explain the numbers like I just did that you think calculated the chance of pulling a red ball is 2%???
We just established that the 2% is the percentage of blue balls that are in the red bag, not the chance of pulling a red ball.
2% can refer to more than one thing.
Shall I show you the contradiction in your position now?
Yeah, 2% can refer to 1 out of 50 green balls too, but that is not what we are talking about.
You agreed that 98% of total blue balls are in the blue bag, and 2% of the blue balls are in the red bag.
So in the blue bag we have 98% of all blue balls and in the red bag we have 100% of all red balls. Put that in your pipe and smoke it! 
Okay, thank you for giving me something to smoke, I’d like to show you the contradiction you’re not acknowledging in your position but I’d like to confirm that you’re listening first.
Post whatcha got!
We have to go all the way back here:
You have agreed that, after selecting the first blue ball, there’s a 98% chance that the bag in front of you contains only blue balls.
Which means there’s a 98% chance that the bag in front of you contains 0 red balls.
You’ve also then confirmed "the bag in front of you has at least a 49.5% chance of having a red ball inside it. "
There’s a 98% chance that the bag contains 0 red balls, and a 49.5% chance that the bag has a red ball.
These two probabilities are incompatible with each other. They cannot both be true.
I misunderstood what you are saying.
You’ve agreed with it numerous times, with a few different ways of phrasing it. Here’s one of those times in your own words:
So what is the other 2%?
I’ve been desperately trying to talk to you about the contradiction for pages now. I’ve politely allowed you to sidestep the topic, interrupt and ignore my points and follow along with your line of questions, but now’s the time that I’m not going to budge until you acknowledge what I’ve said here.
Those two probabilities are fully incompatible with each other, but they are both the necessary implications of your positions here.
I’ll answer your questions about “other 2%” when you start engaging with the things I’m saying.
Again, you do not seem to acknowledge that the 2% is the FACT (not a probability) that 1 blue ball is in the red bag.
You have not responded to the contradiction, so I’m still waiting for that. What do you think of the contradiction? That’s my focus, and I’m not happy to change the subject until it’s acknowledged.
You don’t have to agree, but that’s all I’m interested in talking about at this point. If you think there’s not a contradiction, why not?
It’s not a contradiction until it’s proven to be so. I have not seen proof that it is a contradiction! The 2% is part of the line of questioning and you are skirting the issue!
A is 98%
Not A is 49.5%
These probabilities sum to more than 100%. They can’t both be true, one of them has to be true, they have to sum to 100%. In terms of probability theory, you cannot hold both of these positions, it’s a contradiction.
The 98% is 50 of 51
The 2% is 1 of 51
They sum to 100%, 51 of 51, which makes your claim that there is a 2% chance of picking a red ball irrelevant to those numbers. 51 Blue balls have NOTHING to do with 2% chance of picking a red ball next.
Here is what you are saying:
50 of 51 blue balls are in the blue bag, so that leaves 2% chance to pick a red ball next.
That is nonsense!
It is 50 of 51 blue balls are in the blue bag and 1 of 51 blue balls are in the red bag.
There’s a 98% chance that the bag contains 0 red balls, and a 49.5% chance that the bag has a red ball.
That’s your position. Those don’t sum to 100%.
Again, the 98% is 50 of 51. The 49.5% is 49 of 99.