It is pointless in the sense is that it is a necessary truth, it is a principle of logic. But it isn’t pointless in the sense that it also means, “If p is true then it isn’t true that necessarily it isn’t true that p is true”. This indicates that “p is true” isn’t necessarily true. It is possibly false. That is why there is another principle of logic, which states that, “If necessarily p is true, then p is true”. So it isn’t an understatement. Necessity implies actuality and actuality doesn’t imply necessity and actuality implies possibility.
As the proof goes on to show, it is found that the Hypothesis you highlight does eventually lead to a contradiction. That’s why premise (7) shows a Contradiction. But the Contradiction only comes about when we combine the hypothesis (5) with the rule of inference (DR). You can’t obtain the contradiction otherwise.
You appear to have confused two distinct statements as one and the same.
(S1) p is true. [symbol: p] p is true
(S2) Know that p is true. [symbol: Kp] know p is true
The negation of these two statements:
(S1*) it isn’t true that p is true. [~p] p isn’t true
(S2*) it isn’t true that know that p is true. [~Kp] Don’t know p is true
As you can see, (S1) doesn’t have any logical operator working upon it. (S2) has a logical operator working upon it, i.e K or Know that. (S1) is contained within (S2), but (S2) isn’t contained within (S1). It is a logical asymmetry. They can both be true, but they can’t both be false. In other words, Some ravens are black and Some ravens are not black, i.e. subcontraries.
Since your second fault you find in the proof is based on the same mistake you made with the first fault you find in the proof, the response to you confusing two logical statements as equivalent overrides both points you make. Your own highlighting indicates this as well. You highlight the operator “isn’t true that” and never the statement it operates on. While you highlight a proposition “p is true”.
And it appears to me that you have ignored what the processes that was going on here. It was a logical Reductio Ad Absurdum. It showed that a contradiction could be arrived from combining certain hypothesis, which implies their negations are necessarily true. It is not possible that they are false. And each point of your criticisms have been over premises that contained p&~Kp, which in turns moves back to the hypothesis of Fallibilism. Your criticism fits with what I stated, which is that you reject Principle of Fallibilism, or that there are things that are true and that don’t know true.
[Edit]
You make an attempt at logical statements to show where I was wrong, but your criticism shows your own confusion when spelled out. Your confusion is that of having a conditional without a consequent, which is like being a bachelor with a wife.
(1) carries no logical content. It isn’t a WFF, or Well Formed Formula for logic to handle. You use (1) to make an analogy with (1*) which is obviously a WFF, or a Well Formed Formula for logic to handle. You present conditional statements with only antecedents and no consequents, or antecedents with no logical implications (i.e. consequences). What I presented, however, has logical implications.
(1)-(3) all have the problem of not WFF, or Well Formed Formulas, and are logically meaningless. Logic can’t handle them or make a determination on it. Now you can modify them by adding consequences, i.e. if p and q, then r (Aristotelian Syllogisms), or drop the conditional and just make them into conjunctions, i.e. p is true and believe that p is true.
So my proof contains WFFs and your examples or criticisms aren’t WFF. Your examples need to be modified into conditional or conjunction.Since your criticisms aren’t even WFFs, they can’t be contradictions.