Lots of odd numbers in nature. Golden ratio & what not.
I mean I’m not sure about the exact numbers, because of all the other combinations present, but it would not be 50 50 in any case.
Of course it’s not going to be 50/50, you’ve taken a randomized data set and removed all streaks of Heads, but kept all streaks of Tails. What does that prove, other than that removing streaks of one leaves more of the other?
Both faulty, because I asked for all aaax instances, and you gave other combinations mixed in with them, which offsets the distribution.
You didn’t even include the margin of error calculator that I asked for.
The first experiment literally just counts the Xs of all AAAXs that occur. Of course there are other ‘combinations mixed in with them’, it’s a random coin flip. I don’t have a coin that can flip three heads and then an X at will. If I did, it wouldn’t be a fair coin, would it?
Correction: it’s a series of random coin flips.
I’m extremely confused about why you think it’s possible to design a fair experiment, with a fair coin, that ends reliably in a series of coinflips with an AAAX followed immediately by another AAAX, followed immediately by another and another and another.
If it’s a fair coin, that pattern will not come out. What are you smoking, that you think asking for that is remotely reasonable?
Write me this program then:
Only count the aaax combinations that occur after all previous flips give a 50 50 distribution of a’s and b’s with a given margin of error of your choice.
If A means heads, X means tails… no? If X means random, is A forced? Just curious. P.s. DNA man!
I assume X means heads or tails, that’s how I’ve been using it.
Just write a program that “randomly” spits out 3 A’s then randomly tosses for an A or B.
See if you get a 50/50 distribution of AAAA to AAAB.
I used the word “is” instead of “isn’t”
What I meant to say is that in a universe of randomness…
There’s no reason why heads won’t come up an infinite number of times with a non weighted coin.
So basically, the first program I wrote, but only count the Xs if the distribution of previous heads to tails is between 49.9 and 50.1, yeah?
That’s what it sounds like he’s asking for half the time. Doesn’t it?
May the odds be ever in your favor. lolz
Yes, for fuck’s sake, x is a or b.
Origami, reply to this please
Only if the distribution of previous heads to tails before the first a in the aaax combination is between 49.9 and 50.1, yes.
Is A not always X then???