Hi Farsight,
A topology formally is an ordered pair consisting of a set S and a class of open subsets of S, which by definition includes S and the null set. Informally, we can speak of the class of open sets as a topology because S is included in the open sets.
A given set, in general, may have a number of different topologies. Therefore a given set, such as a moebius strip without a definition of its’ open sets, is not formally part of the study of Topology.
The reason that Topology and metrics are related is because a given metric on a set S can define open balls in that set, which in turn can uniquely generate the class of open sets of S.
Once the topology is generated, frequently by using a specified metric, two different topological sets can be related.
It turns out that the concept of continuous functions can be generalized by showing that a function maps open sets to open sets. Most interestingly, functions that are not continuous can be made continuous by defining the image of open sets to be open sets in the range of the function.
Two sets, with their specified topologies, are defined to be topologically equivalent if and only if there exists a continuous bijection (a one to one and onto map) of the two sets.
At this point, equivalency classes exemplified by certain well known objects such as the Real plane can be established. It turns out that the moebius strip, a doughnut, and a cylinder and others are all topologically equivalent to the Real plane.
Personally, I think examining various topologies to see if they can generate metrics, and vice versa is more interesting.
In any case this brings us back to the metric that you are using for your space.
I have made three drawings to illustrate the problem of simply saying that you use motion for your metric.
Figure 1:

In this picture we are assuming that there is no passage of time.
The classic Euclidean answer, and the engineers will get testy if you don’t give very nearly this answer, is that the distance from Particle 1 to Particle 2 is + square root (14).
However your answer, if taken literally, is 0.
Figure 2:

Here I have changed z to t.
The relativistic answer is that the distance from Particle 1 to Particle 2 is + square root (5 – 9c^2).
Again, unless you assume that the particles are moving, your answer is 0.
Even if you assume that the particles are stationary and only passing through time, the change in the spatial dimensions would be 0 and again your answer would be 0.
Figure 3:

Here, assuming that Particle 1 is stationary and Particle 2 is moving with velocity v, there is actually a possibly meaningful interpretation. If we let v[size=85]x[/size] be the coefficient of the vector v[size=85]x[/size] and v[size=85]y[/size] be the coefficient of the vector v[size=85]y[/size] then one possible metric could be d = square root (v[size=85]x[/size]^2 + v[size=85]y[/size]^2).
Additionally, we could be looking at space as a curved surface, embedded in a Euclidean space, where x = f[size=85]1[/size](q, r, s), y = f[size=85]2[/size](q, r, s), z = f[size=85]3[/size](q, r, s) and t = f[size=85]4[/size](q, r, s).
However, there are numerous possible metrics and it could get complicated after that. I am left uncertain about what you mean.
If you have a rigorous formal definition, I would appreciate it, if you would share it with me.
Thanks Ed


